Grouping partial table data on SQL -

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i have table data below. in scenario, employee can have either 1 or 0 or (1 , 0) never employee exists combination of multiple 1 , multiple 0.

employee status

<table>  	<tr>  		<th> employee</th>  		<th> status </th>     <tr>    <tr>  		<td>abc </td>  		<td> 1</td>    </tr>      <tr>  		<td>abc </td>  		<td> 1</td>    </tr>      <tr>  		<td>pqr </td>  		<td> 1</td>    </tr>      <tr>  		<td>xyz </td>  		<td> 0</td>    </tr>  </table>

below expected output.

<table>  	<tr>  		<th> employee</th>  		<th> status </th>     <tr>      <tr>  		<td>abc </td>  		<td> $</td>    </tr>      <tr>  		<td>pqr </td>  		<td> yes</td>    </tr>      <tr>  		<td>xyz </td>  		<td> no</td>    </tr>  </table>

that means, if there duplicate records status should $, if 1 yes , if 0 no.

thank in advance helping on this

what have tried:

;with ctee (rownumber, employeename, [status])  (select a.rownumber,         a.employeename,          case when a.rownumber > 1 ''               when a.rownumber = 1 , working = 0 'n'               else 'y' end [status]   (select row_number() over(partition employeename order employeename) [rownumber],        employeename,         [status]         [table]         group employeename, [status] ) )   select employeename, [status]  ctee c1  (rownumber = 1  , employeename not in         (select employeename          ctee employeename = c1.employeename , [status] = '')) or rownumber =2

there lot of approaches this, here 1 uses derived tables count():

select t.employee,        case when cnt > 1 '$'             when cnt = 1 , status = 1 'yes'             else 'no' end 'status'         (select distinct employee, status              table) t inner join  (select count(status) 'cnt', employee              table              group employee) t2 on t2.employee = t.employee

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