print a paragraph that contains more than 2 patterns using awk or sed -

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i want print paragraphs begin "select" , end ";", should contain "in cccc" example if have following code 

select aaaa bbbb in cccc ; select dddd eeeee in ffff ; select rrrr eeeee in cccc ;

the result 

select aaaa bbbb in cccc ; select rrrr eeeee in cccc ;

so here's awk used awk '/^select*/,/^;/{if ($0 ~ /^in cccc/) ; print}' inputfile result entire content of file

you can try awk:

awk 'begin{ors=rs=";"} /^[[:space:]]*select.*in cccc/' file

here,

  • ors - output record separator
  • rs - input record separator

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