php - Mysql Insert form into database table PDO -

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i have problem.. tried today lot make working seems impossible me.. decided ask here. have form needs added on database table when submit button pressed. php code use.. removed tries btw:

<?php   $pdo = new pdo('mysql:host=;dbname=', '', '');   $sql = "select * games limit 10";   foreach ($pdo->query($sql) $row) {   ?>

my html code (form):

<form class="form-group" method="post" action="">  	<div role="tabpanel" class="tab-pane active" id="home">  		<div class="form-group" style="margin-top: 15px;">  			<label for="exampleinputemail1">game title</label>  			<input type="text" class="form-control" id="exampleinputemail1" placeholder="" name="gtitle" />  		</div>  		<div class="form-group">  			<label for="exampleinputpassword1">youtube link</label>  			<input type="text" class="form-control" id="exampleinputpassword1" placeholder="" name="ytlink" />  		</div>  		<div class="form-group">  			<label for="exampleinputpassword1">link source</label>  			<input type="text" class="form-control" id="exampleinputpassword1" placeholder="ex: gleam, dlh, failmid, hrkgame, indiegala, other, steam" name="slink" />  		</div>  		<div class="form-group">  			<label for="exampleinputpassword1">link free steam keys</label>  			<input type="text" class="form-control" id="exampleinputpassword1" placeholder="key must give +1 steam library game count" name="keysl" />  		</div>  		<label for="exampleinputpassword1">steam app id</label>  		<div class="input-group" style="padding-bottom: 10px;">  			<span class="input-group-addon" id="basic-addon3">http://store.steampowered.com/app/</span>  			<input type="text" class="form-control" id="basic-url" aria-describedby="basic-addon3" placeholder="app id" name="appid" />  		</div>  		<div class="form-group">  			<label for="exampleinputpassword1">categories</label>  			<div class="checkbox">    				<label class="radio-inline">  					<input type="radio" name="inlineradiooptions" id="inlineradio1" value="option1" /> 1  					<h4><span class="label label-success">keys available</span></h4>  				</label>  				<label class="radio-inline">  					<input type="radio" name="inlineradiooptions" id="inlineradio2" value="option2" /> 2  					<h4><span class="label label-danger">no keys left</span></h4>  				</label>      			</div>  			<button type="submit" class="btn btn-default" name="insert">submit</button>  		</div>  	</div>    </form>

thank me.

try , in radio button put value '1' , '2' instead of 'option1' , 'option2'

        if(isset($_post['insert']))     {         $game_title=$_post['gtitle'];          $youtube_link=$_post['ytlink'];         $link_source=$_post['slink'];         $link_steam_keys=$_post['keysl'];         $app_id=$_post['appid'];         $categories=$_post['inlineradiooptions'];          $query_ins="insert tbl_game(game_title,youtube_link,link_source,link_steam_keys,app_id,categories) values(:game_title,:youtube_link,:link_source,:link_steam_keys,:app_id,:categories)";         $stmt_query=$dbh->prepare($query_ins);         $games_ins=$stmt_query->execute(array(":game_title"=>$game_title,":youtube_link"=>$youtube_link,":link_source"=>$link_source,":link_steam_keys"=>$link_steam_keys,":app_id"=>$app_id,":categories"=>$categories));         if(!$games_ins)         {             $error=$stmt_query->errorinfo();             echo $error['2'];         }     }

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