Bash. infinite loop showing a counter and more info -

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i have script generates dinamically bash script. in heredoc script there infinite loop showing counter (this works!):

date1=`date +%s` while true;     echo -ne "$(date -u --date @$((`date +%s` - $date1)) +%h:%m:%s)\r"; done

this loop working fine if put this. problem need show not counter. more info needed (some static data). i'll put not working code:

#!/bin/bash dir="/tmp/" my_file="generatedscript.sh"  rm -rf "$dir$my_file" > /dev/null 2>&1  exec 3>"$dir$my_file"  cat >&3 <<-'eof'     #!/bin/bash     date1=`date +%s`     while true;         echo -ne "info\n" # damned line, if remove counter works fine         echo -ne "time counter: $(date -u --date @$((`date +%s` - $date1)) +%h:%m:%s)\r";     done eof  exec 3>&-  xterm -hold -geometry 78x25+0+0 -t "testing" -e "bash \"$dir$my_file\"" > /dev/null 2>&1 &

this shows xterm window lot of lines , info line overlapped "time" word of other line. want show info line separately time counter line , counter running... , once!

if remove line echo -ne "info\n" counter showing ok, running , once... how can put different line (echo info) above , fixed line without repetition? possible? idea of how reach this? thank you.

just move info line out of loop. prefer put carriage return @ start of line. neither -n or -e portable, prefer printf simplest uses of echo.

dir="/tmp/" my_file="generatedscript.sh"  script="$tmp/$my_file" cat > "$script" <<'eof' echo info date1=$(date +%s) while true;   now=$(date +%s)   delta=$((now - date1))   printf '\rtime counter: %s' "$(date -u --date "$delta" +%h:%m:%s)" done eof chmod +x 500 "$tmp/$my_file" xterm -hold -geometry 78x25+0+0 -t "testing" -e "$script" > /dev/null

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