sqlalchemy - Filter results by count of items in relationship -

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let's have these 2 models :

def client(db.model):     id = db.column(db.integer, primary_key=true)     invoices = db.relationship('invoice', backref='client')   def invoice(db.model):     id = db.column(db.integer, primary_key=true)

i'd retrieve client @ least 1 invoice , less 20 invoice. expecting work :

client.query.join(invoice).filter(and_(invoice.count() > 1, invoice.count() <= 20))

or nice :

client.query.join(invoice).filter(and_(count_(invoice) > 1, count_(invoice) <= 20))

but of course, can't simple. .count() can't work there , can't find count_() in sqlalchemy.func.

thanks coworkers , code lying around, got working:

    client = client.query\         .outerjoin(client.invoices)\         .group_by(client)\         .having(\              func.and_(\                  func.count_(client.invoices) >= 1)\                  func.count_(client.invoices) <= 20)\              )         ).all()

i hope helps someone!


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