php - Compare Multiple coloumns in MySql -

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i need compare 2 different columns in table: tbl_try (country, name). if there 2 coloumns same value nothing. if there no same values of these 2 columns same insert.

this connection database:

      <?php         require_once("menu.php");         require_once("function.php");      ?>

here main code (read comments try understand)

            <?php              $conn = connecttosql();               $query= "select *  tbl_countries";              $result = mysqli_query($conn, $query)              or die("error in query: ". mysqli_error($conn));               $choose = '';              while ($row = mysqli_fetch_assoc($result))             {                  $choose .= '<option value = "'.$row['name'].'">'.$row['name'].'</option>';             }              ?>         <div class="form-group">           <label class="control-label col-sm-2" for="country">choose country:</label>           <div class="col-sm-5">               <select class="form-control" name ="reg_country" >                   <option></option>                   <?php echo $choose;?></select>           </div>             </div>             <br>             <div class="form-group">           <div class="col-sm-offset-4 col-sm-10">             <button type="submit" name="submit" class="btn btn-default">submit</button>           </div>         </div>              <?php               if(isset($_post['submit']))              {                  $country = $_post['reg_country'];                  $_session['country'] = $country;                      $query2 = "select name,id tbl_flowertypes ";                  $result2 = mysqli_query($conn, $query2) or die("error in query: ". mysqli_error($conn));                  $result2_rows = mysqli_num_rows($result2);                 //this code not working. need count 2 columns (name , country)                // if in tbl_try there country:italy name:12 red roses. nothing if there no data same               // insert data                  $query3 = "select count(*) tbl_try name='$_session[flower_type_name]' , country ='$_session[country]' ";                    $result3 = mysqli_query($conn, $query3) or die("error in query: ". mysqli_error($conn));                  $result3_rows = mysqli_num_rows($result3);                    // loop counting how many record in table flowertype , loop insert data in tbl_try (this code working fine)                  for($i = 1; $i <= $result2_rows;$i++)                 {                        while($row = mysqli_fetch_assoc($result2))                         {                              $_session['flower_type_name'] = $row['name'];                         // insertion of data                             $inserting = "insert tbl_try(name,country) values ('$row[name]','$_session[country]')";                             $result3 = mysqli_query($conn, $inserting) or die("error in query: ". mysqli_error($conn));                          }                    }              }

the result need be:

the database need in insertion once . if there no same columns in table. if there same data nothing.

i need complete code showing table records know how that.

any suggestions?

the best way add unique definition 2 columns db this:

alter table tbl_try add unique (name, country)

then can check result code db , on basis of result code now, if row stored db or not due case, same name , country in db.


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