PHP json_decode error: Array value found, but an object is required -

i trying decode following json file

{      "email": "mail@gmail.com",      "password": "12345",      "languageproficiency": {             "language": "english",              "proficiency": 4    },      "tags": [          {             "name": "singing"          },          {            "name": "dance"          }    ] } 

when this

 $data = json_decode($jsoncontent, true);  echo $data;  die(); 

i have following error:

array value found, object required

question

1) how can view data json 2) how can access property of each object in tags array

i validating json content againsts schema

  {     "$schema": "http://json-schema.org/draft-04/schema#",     "type": "object",     "properties": {       "email": {         "type": "string"       },       "password": {         "type": "string"       },       "languageproficiency": {         "type": "object",         "properties": {           "language": {             "type": "string"           },           "proficiency": {             "type": "integer"           }         },         "required": [           "language",           "proficiency"         ]       },       "tags": {         "type": "array",         "items": {           "type": "object",           "properties": {             "name": {               "type": "string"             }           },           "required": [             "name"           ]         }       }     },     "required": [       "email",       "password",       "languageproficiency",       "tags"     ]   } 

update

i tried following view json content

 print_r($data) 

but still same error

$data = json_decode($jsoncontent, true);

above line of code return array, can not use echo directly print array.

to print specific value of array (e.g. email), this:

echo $data["email"]; 

---

tip:

use print_r() know array structure this,

echo "<pre>"; print_r($data);